Energy in a current carrying coil is stored in the form of

If the current in an $LR$ circuit is reduced to half,what will be the energy stored in it?

The magnetic energy stored in an inductor of inductance $4\,\mu H$ carrying a current of $2\,A$ is:

The magnetic potential energy stored in a certain inductor is $64 \times 10^{-3} \ J$,when the current in the inductor is $80 \ mA$. The inductance of this inductor is: (in $H$)

$A$ coil of inductance $2\, H$ having negligible resistance is connected to a source of supply whose voltage is given by $V = 3t$ volt (where $t$ is in seconds). If the voltage is applied when $t = 0$,then the energy stored in the coil after $4\, s$ is ............ $J$.

The magnetic energy stored in an inductor of inductance $4 \ H$ carrying a current of $1.5 \ A$ is